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X^2-0.75X-3.35=0
a = 1; b = -0.75; c = -3.35;
Δ = b2-4ac
Δ = -0.752-4·1·(-3.35)
Δ = 13.9625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.75)-\sqrt{13.9625}}{2*1}=\frac{0.75-\sqrt{13.9625}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.75)+\sqrt{13.9625}}{2*1}=\frac{0.75+\sqrt{13.9625}}{2} $
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